Question

If alpha and beeta are zeroes of p(x)=x^2-5x+a such that alpha - beeta=1, then find a.

Answer 1

X^2-5x+a

alpha + beta = -b÷a

Alpha + beta = 5÷1 ------1

= 5

Alpha = 1+ beta ---------2

from 1

Alpha = 5- beta ---------3

1+ beta = 5- beta

-4 = -2beta

4= 2 beta

Beta= 2

From 2

Alpha = 1+ beta

Alpha = 1+2=3

We know that

Alpha* beta = c÷a

3*2=a

a=6

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