Question

if alpha and beeta are zeroes of polynomial x^2-4√3x+3 then find the valueof alpha +beeta -alpha ×beeta​

Answer 1

Answer:

√3(4 - √3)

Step-by-step explanation:

Given : p(x) = x² - 4√3x + 3

On comparing this with ax² + bx + c, we get

a = 1, b = - 4√3, c = 3

It is given that α and β are the zeroes of the above polynomial.

Now,

• Sum of zeroes = α + β = - b/a

→ α + β = - (- 4√3)/1

→ α + β = 4√3

• Product of zeroes = αβ = c/a

→ αβ = 3/1

→ αβ = 3

To Find : α + β - αβ

Putting known values in it.

→ (4√3) - (3)

→ 4√3 - 3

→ √3(4 - √3)

Answer 2

alpha+beeta=-b/a

-(-4√3)/1=4√3

-alpha *beeta=c/a

3/1