Question

IF ALPHA AND BEETA ARE ZEROS OF X2-6X+8
FIND ALPHA/BEETA+BEETA/ALPHA

PLZ ANSWER
WILL DEFINITELY MARK BRAINLIEST

Answer 1

Answer:

5/2

Step-by-step explanation:

x² - 6x + 8 = 0

x² - 2x - 4x + 8 = 0

x*(x - 2) - 4*(x - 2)

(x - 4)*(x - 2)

So,

α = 4

β = 2

α/β + β/α

= 4/2 + 2/4

= 5/2

Answer 2

IoQUESTION.


IF ALPHA AND BEETA ARE ZEROS OF X2-6X+8
FIND ALPHA/BEETA+BEETA/ALPHA



TOPIC

QUADRATIC EQUATIONS


SOLUTION.



GIVEN



QUADRATIC EQUATION




${x}^{2} - 6x + 8$



$\alpha \: \: and \: \beta \: are \: roots \: \: of \: eq$







STEP (1)




FACTORIES THE GIVEN EQ




$= {x}^{2} - 6x + 8$





$= {x}^{2} - 4x - 2x + 8$





$= x(x - 4) - 2(x - 4)$





$= (x - 2)( x - 4)$




ROOTS ARE



$(x - 2)$



$= > x = 2$


MEAN.
$\alpha = 2$



2ND ROOT



$(x - 4)$



$x = 4$




$\beta = 4$




STEP 2


$\frac{ \alpha }{ \beta } + \frac{ \beta }{ \alpha }$




$= \frac{2}{4} + \frac{4}{2}$






$\frac{2 + 8}{4}$





so Ans


$\frac{5}{2}$