Question

If alpha and beeta ate the zeros of the p(x)=ax^2+bx+c, then the other polynomial whose zeros are alpha ^2/beeta and beeta^2/alpha

Answer 1

Answer:

3abc-b^3 /ca^2

Step-by-step explanation:a^3+b^3/an

(A+b)^3-3ab(a+b) /ab

Sub a+b = -b/a

ab= c/a