Question

if alpha and beta are roots of equation ax^2+bx^+c=0 then find alpha minus beta or say alpha minus beta formula

Answer 1

Alpha - beta = - b/c

Answer 2

Here is your answer,
${( \alpha - \beta )}^{2} = { \alpha }^{2} + { \beta }^{2} - 2 \alpha \beta \\ \alpha - \beta = \sqrt{ { \alpha }^{2} + { \beta }^{2} - 2 \alpha \beta } \\ \alpha - \beta = \sqrt{ {( \alpha + \beta )}^{2} - 2 \alpha \beta - 2 \alpha \beta } \\ \alpha - \beta = \sqrt{( \alpha + \beta )( \alpha + \beta ) - 4 \alpha \beta }$

Now, if you have to find the value of Alpha minus beta you need to only find the value of alpha + beta and alpha beta.

$\alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a}$