if alpha and beta are roots of the equation 3 X square + kx + 8 is equal to zero and Alpha upon beta is equal to 2 by 3 then find the value of k
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3x^2 + kx + 8 = 0_______α,β
α/β = 2/3 => α = (2/3)β
We know, α + β = (-k)/3_______(1)
and α × β = 8/3 => (2/3)β × β = 8/3
=> β^2 = 4 => β = 2 or -2
=> α = 4/3 or -4/3
So, α + β = 2 + 4/3 or -2 -4/3
=> α + β = 10/3 or -10/3
Comparing these values with equation (1), we get
k = ±10
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