Question

if alpha and beta are roots of the quadratic equation 3 x 2 - 6 X + 2 = 0 then the value of Alpha 3 + beta 3 is

Answer 1

3x^2-6x+2=0
dividing by 3 we get
x^2-2x+2/3=0
(X-2/2)^2-(2/2)^2+2/3=0 ( it's a trick for finding the root)
(X-1)^2+2/3-1=0
(x-1)^2=1-2/3
(x-1)^2=1/3
X-1=+-1/√3
for X-1=1/√3 I For X-1=-1/√3
X=1+1/√3 I X=1-1/√3
X=(√3+1)/√3 I X=(√3-1)/√3
X=(3+√3)/3=alpha I X=(3-√3)/3= beta

According to the question
Alpha*3+Beta*3=?
(3+√3)/3*3 + (3-√3)/3*3 = 3+√3+3-√3= 3+3= 9
Thats ur answer...
If u satisfied mark this as brainiest..