if alpha and beta are roots of x2+bx+c=0,(alpha*beta)=3 and a,b,c are AP then find value of alpha+beta?
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ax^2 + bx + c = 0
alpha*beta = 3
this implies that,-b/a = 3
-b = 3a
Also,a,b,c, are in AP.
2b = a + c
2(-3a) = a + c
-6a - a =c
-7a = c
alpha+beta = c/a
c/a = -7a/a = -7
alpha + beta = -7.
alpha*beta = 3
this implies that,-b/a = 3
-b = 3a
Also,a,b,c, are in AP.
2b = a + c
2(-3a) = a + c
-6a - a =c
-7a = c
alpha+beta = c/a
c/a = -7a/a = -7
alpha + beta = -7.
yash230:
sorry....but its wrong.... answer is 1
(alpha beta)=3
Is the process right ?
no
I am so sorry. You can delete my answer if it is not correct.
okkk....
but delete option is not showing
hey can u solve my new questions???
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