Question

if alpha and beta are the quadric polynomial x²-7x+p such that alpha²+beta²=29.find the value of p

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{Question}}$

If alpha and beta are the quadric polynomial x²-7x+p such that alpha²+beta²=29.find the value of p

$\huge\underline{\underline{Answer}}$

Let,..

$\alpha \: \: and \: \: \beta \: \: be \: roots \: of \: following \: equation...$

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alpha + beta = -b/a = -(-7) /1 = 7

(alpha) × (beta) = p

alpha²+beta² = (alpha + beta)² - 2(alpha)(beta)

= alpha² + beta² + 2(alpha)(beta) - 2(alpha)(beta)

= alpha² + beta²

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Here given that=>

alpha²+beta²=29

(alpha + beta)² - 2(alpha)(beta) = 29

49 - 2(p) = 29

2p = 49 - 29

2p = 20

p = 10

So,( p = 10) is solution of given question..

Answer 2

Answer:

Ans is 10

Step-by-step explanation:

p=10 Hello Guys