If alpha and beta are the roots of 2x^2- 3x+1=0,find a new polynomial whose zeroes are 3 alpha and 3 beta.
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Answer:
Step-by-step explanation:
2x2-9x+9
Step-by-step explanation:
Alpha + beeta=-b/a
=3/2
Alphabeeta=c/a
=1/2
3alpha +3beeta=3(alpha+beeta)
=3×3/2=9/2=-b/a
3alpha×3beeta=9alphabeeta=9×1/2
=9/2=c/a
a=2 b=-9 c=9
Therefore quadratic polynomial= 2xsquare-9x+9
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