Question

if alpha and beta are the roots of 2x^2+x+3=0'then the equation whose roots are 1-alpha by 1+alpha and 1-beta by 1+beta​

Answer 1

Step-by-step explanation:

from 2x^2+x+3=0,a+b=(-.5) &

ab=3/2

calculate [(1-a)/(1-a)]+[(1-b)/(1+b)] & then calculate [(1-a/(1+a)]×[(1-b)/(1+b]

apply this in a typical quadratic eqn and ans will be there.