if alpha and beta are the roots of 6x^2-7x-3=0 find the value of alpha square + beta square
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6x^2-7x-3=0
6x^2-9x+2x-3=0
3x(2x-3)+1(2x-3)=0
alpha=3x+1=0 beta=2x-3
alpha=-1/3 beta=3/2
alpha ^2+beta^2
(-1/3)^2+(3/2)^2
=1/9+9/4
=4+81/36
=85/36
6x^2-9x+2x-3=0
3x(2x-3)+1(2x-3)=0
alpha=3x+1=0 beta=2x-3
alpha=-1/3 beta=3/2
alpha ^2+beta^2
(-1/3)^2+(3/2)^2
=1/9+9/4
=4+81/36
=85/36
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