Question

If alpha and beta are the roots of equation 3x^2 + x - 10 = 0 , then the value of 1/alpha +1/beta is .............?

Answer 1

3x² + x - 10 = 0

Sum of zeroes = ã ( alpha) + ß ( beta) = - b / a

= - 1 / 3

Product of zeroes = ã × ß = c / a = - 10 / 3

Now 1 / ã + 1 / ß

So ã + ß / ã ß ( By taking LCM)- -

= - 1 / 3 ÷ - 10 / 3

= - 1 / -10

= 1 / 10

Thus the value of 1/alpha +1/beta is = 1 / 10

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Answer 2

Step-by-step explanation:

3x

2

+x−10=0

α,B are roots

⇒α+B=

a

−b

=

3

−1

αβ=

a

c

3

−10

α

1

+

β

1

=

(αβ)

(α+β)

=

−(10)/3

(−1/3)

⇒

10

1

∴

α

1

+

β

1

=

10

1