If alpha and beta are the roots of the equation 2x^2-3√3x-5=0 find the value of alpha^2+beta^2
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Answered by
2
by using identity --(a+b)²=a²+b²+2ab .......this question can be done .
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shwethu2k3:
But I am getting 27/4
have I done any mistake in my calculation ??
oh ! i am very sorry . I have took wrong value
Please tell me the correct answer
Please
i am getting 47/4
Ys it's absolutely write
Answered by
9
Alpha + beta = -b/a
= - ( - 3√3) / 2
= 3√3 / 2...............1)
Alpha × beta = C/a
= -5/2.................2)
(Alpha + beta )^2 = Alpha^2 + beta^2 + 2Alpha × beta..
So, Alpha^2 + beta^2 = (Alpha + beta )^2 - 2Alpha × beta............3)
Substitute 1) and 2) in 3)
Alpha^2 + beta^2 = (3√3 / 2)^2 - 2 × - 5/2
= 27 /4+ 5
= 47/4
Hope it helps!!!!!
= - ( - 3√3) / 2
= 3√3 / 2...............1)
Alpha × beta = C/a
= -5/2.................2)
(Alpha + beta )^2 = Alpha^2 + beta^2 + 2Alpha × beta..
So, Alpha^2 + beta^2 = (Alpha + beta )^2 - 2Alpha × beta............3)
Substitute 1) and 2) in 3)
Alpha^2 + beta^2 = (3√3 / 2)^2 - 2 × - 5/2
= 27 /4+ 5
= 47/4
Hope it helps!!!!!
can u see the 3 dots on the side of the answer . click it
and edit ur answer.
i have tried it but it is not helping.
oh i have lost one mark in my exam
its all okay . leave it now .
swethu same story here , i also loose the mark in my exam
i did the same blunder that batra1 did in his answer
u r right .....just because of these silly mistake i loose my 3-4 marks in exams
chalo koyi baat nhi aage se dhyan rakhna . These blunders will never ever reduce our percentage. so be alert and active during maths exam . all the best of good luck for boards.
same to u
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