Question

If alpha and beta are the roots of the equation 2x^2+5x-7=0, form an equation whose roots are a^3 and β^3

Answer 1

Answer:

2x^2+5x-7=0

=> 2x^2+7x-2x-7=0

=> x(2x+7)-1(2x+7)=0

=> (2x+7)(x-1)=0

=> 2x+7=0

=> 2x= -7

=> x= -7/2

again,x-1=0

=> x=1

so, alpha= -7/2 and beeta =1

alpha^3=(-7/2)^3 and beeta ^3=1^3=1

so the equation is {x+(7/2)^3} (x-1)