if alpha and beta are the roots of the equation(a+1)x2+(2a+3)x + (3a+4)=0. if product of alpha and beta is 2 yhen find sum of alpha and beta
Answers
Answered by
55
product of quadratic equations is given by c/a
where c is the constant and a is the coefficient of X*2..
a/q
c/a=(3a+4)/(a+1)=2
3a+4=2a+2
a=-2
sum of alpha and beta is given by -b/a
-((2a+3)/(a+1))
put a=-2
answer =-1
where c is the constant and a is the coefficient of X*2..
a/q
c/a=(3a+4)/(a+1)=2
3a+4=2a+2
a=-2
sum of alpha and beta is given by -b/a
-((2a+3)/(a+1))
put a=-2
answer =-1
Answered by
2
Given,
A polynomial p(x) = (a+1)x^2 + (2a+3)x + (3a+4) = 0
Alpha and beta are the roots of p(x).
The product of alpha and beta = 2
To find,
The sum of alpha and beta.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically,
If alpha and beta are the two roots of a quadratic equation p(x) = ax^2 + bx + c, then;
the sum of the roots = (-b)/a
product of the roots = c/a
{Equation-1}
Now, according to the question;
The product of the roots of p(x) = 2
=> Alpha x beta = 2
=> (3a+4)/(a+1) = 2 {according to equation-1}
=> 3a + 4 = 2(a+1) = 2a + 2
=> a = -2
Now, according to equation-1;
The sum of alpha and beta
= -(2a+3)/(a+1)
= -(2×-2 +3)/(-2+1)
= -1
Hence, the sum of alpha and beta is equal to -1.
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