If alpha and beta are the roots of the equation ax^2+bx+c=0,then the roots of the equation ax^2+b lambda x+c lambda^2 =
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from first equation
alpha + beta= -b/a
alpha x beta= c/a
for second equation let the roots be p and q
p+q = -b lambda/a = (alpha+beta)lambda
pxq = c lambda/a = (alpha x beta)lambda
from this the roots of the second equation are alpha lambda and beta lamda...
hope this helps:p
alpha + beta= -b/a
alpha x beta= c/a
for second equation let the roots be p and q
p+q = -b lambda/a = (alpha+beta)lambda
pxq = c lambda/a = (alpha x beta)lambda
from this the roots of the second equation are alpha lambda and beta lamda...
hope this helps:p
Anonymous:
u r welcome:p
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Answer:
Step-by-step explanation:
from first equation
alpha + beta= -b/a
alpha x beta= c/a
for second equation let the roots be p and q
p+q = -b lambda/a = (alpha+beta)lambda
pxq = c lambda/a = (alpha x beta)lambda
from this the roots of the second equation are alpha lambda and beta lamda...
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