If alpha and beta are the roots of the equation ax2+bx+c=0 then the values of 1/alpha^2 + 1/beta^2 is
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let alpha= A and beta= B (for ease of typing)
then A+ B = -b/a and AB= c/a.
A2+B2= (A+B)^2 - 2AB
= b2/a2 - 2c/a
= b2 - 2ac/ a2
now,
1/A2 + 1/B2
= (B2 + A2)/ AB^2
= (b2 - 2ac/ a2) / (c/a)^2, on simplifying,
= b^2 - 2ac/ c^2. (Answer)
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