Question

if alpha and beta are the roots of the equations sin^2x + psinx + q = 0 and cos^2 + rcosx + s = 0 ; then value of cos(alpha- beta) is​

Answer 1

Answer:

Consider the following equations.     sin2x+psinx+q=0   and   cos2x+rsinx+s=0. Since α  is the root of first equation, we have    sinx=αSince β  is the root of second equation, we have    cosx=βSo the value of cos(α-β)  is given by,     cos(α-β)=cosα cosβ+sinα sinβSubstitute the values to get,      cos(α-β)=βα+αβ  

Answer 2

Answer: (p² + r² - 2)/2

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