if alpha and beta are the roots of the polynomial f(x) = x^2-3x+k such that alpha -beta =1 find the value of k
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Hey
f(x)=x^2-3x+k
Given that @ and ß are the zeros of the polynomial and @-ß=1.............(2)
Now,
@+ß= -(3)=3...................(1)
@ß=k...................(3)
We find,
@^2 + ß^2=(@+ß)^2- 2@ß=(3)^2-2k=9-2k.......................(4)
Thus,
Squaring (2),
(@-ß)^2=(1)^2
=>@^2+ß^2-2@ß=1
=>9-2k-2k=1 [Using (3) and (4)]
=> -4k= -8
=>k=2
I used @ and ß instead of alpha and beta respectively.
I hope it helps you.
It can also be solved by adding(1) and (2). Hence, finding individual values of @ and ß.Then multiplying them which is equal to k.
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