If alpha and beta are the roots of the quadratic equation 3xsquare+kx+8=0and alpha/beta is 2/3 then find the value of k
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ALPHa/Beta = 2/3 so 3alpha=2beta .....sum of the zeroes alpha +beta =-k/3 so alpha=2beta/3 (4)substitute eq in sum of zeoes you will get k = -5 beta .... product of zerors = 8/3 that is alpha × beta = 8/3 substitute (4) in this equation .You will get Beta = +/- 2 thus k will be 10 or -10
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