Math, asked by ushausha8119, 1 year ago

if alpha and beta are the roots of x square + 6 x minus 4 equal to zero find the value of Alpha minus beta whole square​

Answers

Answered by Anonymous
5

Answer:

heyyyaa!!!

Step-by-step explanation:

Given:

x^2 + 6x - 4 = 0

 \alpha  \beta

are the roots of this equation..

To find:

(  \alpha  -  \beta )^{2}

Solution:

We know that,Sum of the roots,

 \alpha  +  \beta

Sum of roots = -b/a

b => Coefficient of x

a => coefficient of x^2

Sum of roots = -6/1

=-6

Product of the roots ,

 \alpha  \beta

Product of roots = c/a

c => constant term

Product of roots = -4/1

= -4

We know that,

( \alpha  -  \beta ) ^{2}  = ( \alpha  +  \beta ) ^{2}  - 4 \alpha  \beta

= (-6)^2 - 4(-4)

= 36 +16

=52

The Answer is 52

HOPE U LIKE IT!!!

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