Question

If alpha and beta are the roots of x2+p (x+1) +c then (1+alpha)(1+beta) = plzplzplzplz fast

Answer 1

let p(x) = x²+p(x+1) +c
p(x) = x² +px + (p+c)
compare p(x) with ax²+bx+c
a= 1, b= p, c = (p+c)
given zeroes are α and β
i)α+β = -b/a = -p----(1)
ii) αβ = c/a = (p+c)---(2)
required
(1+α) (1+β) = 1+α+β +αβ

= 1-p +p+c [ from (1) and (2)]
= 1+c