if alpha and beta are the two zero of the polynomial x square minus 4 root 3 X + 3 find the value of alpha + beta minus alpha beta
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Method of Solution:
Equation : x²+4√3x+3
For the Zeroes of Polynomial f(x)= (x²+4√3x+3)
Zeroes of Polynomial = -b/a -(Coefficient of x)/Coefficient of x²
Sum of Zeroes of Polynomial = -4/√2 ÷1 => -4/√2
Sum of Zeroes = -4/√2
Product of Zeroes of Polynomial = C/a =(Constant term)/Coefficient of x²
[ Product of Zeroes = 3/1 => 1 ]
Therefore, We have obtained (a+ß ) = 4/√2
(aß) = 3
According to the Question Statement!
Statement: find the value of alpha + beta - alpha beta
Substitute the obtained value,
alpha + beta - alpha beta
(4/√2) - (1)
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