If alpha and beta are the two zeroes of the quadratic polynomial x^2 +2x -35, find a quadratic polynomial whose zeroes are 1/alpha and 1/beta.
Answers
Answer:
X^2-4x-60
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Step-by-step explanation:
Solution :-
Given that, ɑ and β are the he two zeroes of the quadratic polynomial x^2 +2x -35 .
So,
→ sum of roots = (-b/a)
→ ɑ + β = (-2)/1 = (-2)
and,
→ Product of roots = c/a
→ ɑ * β = (-35/1) = (-35)
______________
Now,
we have to find a quadratic polynomial whose zeroes are 1/ɑ and 1/β.
So,
→ sum of roots = 1/ɑ + 1/β
→ 1/ɑ + 1/β = (ɑ² + β²)/(ɑ * β)
→ 1/ɑ + 1/β = {(ɑ + β)² - 2ɑβ}/(ɑ * β)
Putting values now , we get,
→ 1/ɑ + 1/β = {(-2)² - 2(-35)} /(-35)
→ 1/ɑ + 1/β = {4 + 70} /(-35)
→ 1/ɑ + 1/β = (-74)/35
and,
→ Product of roots = 1/ɑ * 1/β
→ 1/ɑ * 1/β = 1/(ɑβ)
→ 1/ɑ * 1/β = (-1)/35
______________
Therefore,
→ Required Equation = x² - (sum of roots)x + Product of roots = 0
→ x² - (-74/35)x + (-1/35) = 0
→ (35x² + 74x - 1)/35 = 0
→ 35x² + 74x - 1 = 0 (Ans.)