if alpha and beta are the two zeros of a polynomial x^2-5x+6 then the value of 1/alpha^2+1/beta^2 = ?
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13\36 is the answer
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If alpha (@) and beta (&) are zeros of polynomial x^2-5x+6...
From this polynomial @+&=5 and @&=6..
=1/@^2 + 1/&^2
=(@^2+&^2)/(&^2×&^2)
={(@+&)^2-2@&}/(&^2×&^2)
putting values of @+& and @&...
= (5)^2-2(6) / 6^2
= 25-12/36
= 13/36
This is your answer friend...
From this polynomial @+&=5 and @&=6..
=1/@^2 + 1/&^2
=(@^2+&^2)/(&^2×&^2)
={(@+&)^2-2@&}/(&^2×&^2)
putting values of @+& and @&...
= (5)^2-2(6) / 6^2
= 25-12/36
= 13/36
This is your answer friend...
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