if alpha and
Beta are the two zeros of the quadratic polynomial x square - 3 x + 7 find a quadratic polynomial whose zeros are one by Alpha and one by beta
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Solution :
The given quadratic polynomial is
f(x) = x² - 3x + 7
Since α and β are the zeroes of f(x),
- α + β = - (- 3)/1 = 3
- αβ = 7/1 = 7
We have to find the polynomial whose zeroes are 1/α and 1/β, which can be found as
g(x) = (x - 1/α) (x - 1/β)
= x² - (1/α + 1/β) x + 1/(αβ)
= x² - (α + β)x/(αβ) + 1/(αβ)
= x² - 3x/7 + 1/7
= (7x² - 3x + 1)/7
i.e., 7x² - 3x + 1
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