if alpha and beta are the zeries of polynomial x2-p(x+1)+c such that (alpha+1)(beta+1)=0 then find the value of c
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alpha=-1 and betha=-1
polynomial=x2-px-(p-c)=0
sum of zeros= p/1
-1-1=p
-2=p
product of zeros=-(-2-c)/1
-1×-1=2+c/1
1-2=c
c=-1
polynomial=x2-px-(p-c)=0
sum of zeros= p/1
-1-1=p
-2=p
product of zeros=-(-2-c)/1
-1×-1=2+c/1
1-2=c
c=-1
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