Math, asked by jaisinghbisht, 9 months ago

If alpha and beta are the zero and the quadratic polynomial p(x)=x^2-x-4, then the value of 1/alpha^2+1/beta^2-alphabeta is

Answers

Answered by shrutishikha542
0

Answer:

x^2 - x - 4 =0

To find:

\frac{1}{\alpha^2 } + \frac{1}{\beta^2 } - \alpha   \beta

\frac{\alpha^2 + \beta^2  }{\alpha^2\beta^2} - \alpha \beta

\frac{(\alpha + \beta )^2 - 2\alpha \beta}{(\alpha \beta)^2} -\alpha \beta

From The quadratic equation we have

\alpha +\beta = 1\\\\\alpha \beta  = -4

1 -2.(-4)/(-4)^2 - (-4)

1+8/16+4

9/16+ 4 = 73/4

Sorry my mistake

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