If alpha and beta are the zero of quadratic polynomial p(x)=x×2-5x+4 find the value of 1/Alfa +1/beta- 2alfa beta
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=x²-5x+4
=x²-x-4x+4
=x(x-1)-4(x-1)
=(x-4)(x-1)
x-4=0
x=4
α=4
x-1=0
x=1
β=1
THE ZEROES ARE 4 AND 1
=1/α+1/β-2αβ
=(1/4)+(1/1)-(2×4×1)
=(1/4)+1-8
=(1+4-32)/4
=(5-32)/4
=-27/4
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