if alpha and beta are the zero of the polynomial 3x^2-3x-36 then find (1/alpha+1/beta)
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if alpha and beta are the squares of quadratic polynomial 3x^2-3x-36,
we know that : 1/alpha + 1/ beta
= beta / alpha*beta + alpha / alpha*beta
= (beta +alpha)/ (alpha*beta)
= (-3/3) / (36/3)
= -1/12 (answer).
we know that : 1/alpha + 1/ beta
= beta / alpha*beta + alpha / alpha*beta
= (beta +alpha)/ (alpha*beta)
= (-3/3) / (36/3)
= -1/12 (answer).
aswm55:
actually here denominator is negative in spite of the numerator...i m really sorry for mistake , actually as u know that alpha + beta = -b/a ....but don't worry the answer is same i.e., -1/12.....goodbye.!
OK I got it
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