Math, asked by tannu133, 1 year ago

if alpha and beta are the zero of the polynomial 3x2 -2x-7,then find the value of alpha upon beta +beta upon alpha​

Answers

Answered by nikhil7867
0

Answer:

Answer=20

Step-by-step explanation:

3×2-2×-7

6+14

20

Answered by rehanjalees
4

Answer:

Step-by-step explanation:

alfa/beta + beta/alfa

= (alfa^2 + beta^2 )/alfa beta

=[ (alfa + beta)^2 -2alfa beta]/alfa beta

Given polynomial = 3x^2 - 2x ,-7

a =3, b =-2, c=-7

Sum of zeroes = alfa +beta =-b/a =2/3

Product of zeroes = alfa × beta =c/a =-7/3

Substituting these values in the expression that we got above

[(2/3)^2 - 2 × (-7/3)]/(-7/3)

=(4/9 +14/3)/-7/3

=46/9 × 3/-7

=46/3 × -1/7

=-46/51

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