Question

If alpha and beta are the zero of the polynomial x2+6x+2 then the value of 1/alpha+1/beta is

Answer 1

hello users.....

given that 
α and β are the roots of the equation x² +6x +2 = 0

we have to find ;
1/α + 1/β = ?

solution :-
now;
 we know that 
α+β = - (coefficient of x) / (coefficient of x²)
and 
αβ =  (constant term) / (coefficient of x²)

here 
α + β = -6/1 = -6
and
 αβ = 2 /1 = 2 

Now;
1/α + 1/β = (α + β) / αβ    ( taking L.C.M )
= -6 / 2
= -3 answer

✵✵ hope it helps ✵✵

Answer 2

Answer:

-3

Step-by-step explanation:

Equation : x² + 6x + 2 = 0

alpha + beta = -b / a

= -6 / 1

= -6

alpha × beta = c / a

= 2 / 1

= 2

Required Sum : alpha + beta / alpha × beta

: -6 / 2

: -3