Question

if alpha and beta are the zeroes of 21x^2-x-2 find another quadratic polynomial whose zeroes are 2 x alpha and 2 x beta. answer me fasttt///

Answer 1

it will help u........ mark brainnlist
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Answer 2

The answer is given below :

The polynomial is (21x² - x - 2)

= 21x² - 7x + 6x - 2

= 7x(3x - 1) + 2(3x - 1)

= (3x - 1)(7x + 2)

So the zeroes of the polynomial are 1/3 and -2/7.

Let, α = 1/3 and β = -2/7

Now, 2α = 2/3 and 2β = -4/7

So, the required polynomial has factors
(x - 2/3) and (x + 4/7)

i.e., (3x - 2) and (7x + 4)

So, the required polynomial is

= (3x - 2)(7x + 4)

= 21x² + 12x - 14x - 8

= 21x² - 2x - 8

Thank you for your question.