Question

If alpha and beta are the zeroes of 4x^2-x-4, then find the value of 1/2alpha +1/2 beta
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Answer 1

Answer:

Step-by-step explanation:

First we have to factorise the given equation

1. 4x^2-x-4

we cannot apply factorisation method so we apply the formula of finding the roots

x = -b±$\sqrt{b^2-4ac$/ 2a

apply this formula by assuming that a=4,b=1,c=4

then the values of x comes

α = -1+3$\sqrt{7$i/8   β= -1-3$\sqrt{7$i/8

then on solving,the value of 1/2 alpha + 1/2beta

is -1/8

Answer 2

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