Question

if alpha and beta are the zeroes of ax square +bx +c=0 then find alpha/beta+beta/alpha ​

Answer 1

Answer:

Step-by-step explanation:

We know alpha+beta=-b/a

and alpha*beta=c/a

given alpha/beta+beta/alpha

=alpha^2+beta^2/alpha*beta

=alpha^2+beta^2=(alpha+beta)^2-2 alpha beta

=(-b/a)^2-2 c/a

=b^2-2ac/a^2

So answer=b^2-2ac/a^2/c/a

= b^2-2ac/ac

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