If alpha and beta are the zeroes of f(x) = 2x"2 - x -6 then find the value of alpha"2 + beta" 2
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Answer:
=3.25 (or) 13/4
Step-by-step explanation:
first find the value of alpha + beta that in this case is 1/2 and then find value of alpha*beta that is -3 after which as we know that (a + b)^2 -2ab = a^2 + b^2 where a = alpha and b = beta so after substituting the values 1/2 = a+b and -3= a*b
this will give us the eq
a^2 + b^2 = (a +b)^2 - 2ab
=(1/2)^2 - 2(1/2)(-3)
=1/4-(-3)
= 1/4+3
=3.25 (or) 13/4
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