Math, asked by abhijithsadasivan123, 9 months ago

if alpha and beta are the zeroes of p(x)=2x^2-5x+7 find a polynomial whose zeroes are 2alpha +2beta​

Answers

Answered by aditigour56
0

Answer : p(x)=x^2-5x+7

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Answered by ikshityedidha
1

Step-by-step explanation:

2 {x}^{2}  - 5x + 7 \\ equation \: with \: roots \:  \alpha  \: and \:  \beta  \: is  \\  {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta  \\ equation \: with \: roots \: 2 \alpha  \: and \: 2 \beta   \: is  \: \\  {x}^{2}  - 4 ( \alpha  +  \beta ) + 4 \alpha  \beta  \\ 2 {x}^{2}  - 20x + 28

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