Question

if alpha and beta are the zeroes of p(x) = 3x^2-x-2, then findthe quadric polynomial
whose zerosare 1/alpha and 1/beta


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Answer 1

Step-by-step explanation:

p(x) = 3x² - x - 2

Roots of the equation,

p(x) = 0

=> 3x² - x - 2 = 0

=> 3x² - 3x + 2x - 2 = 0

=> 3x( x - 1) + 2(x-1) = 0

=> (3x + 2)(x-1) = 0

x = -2/3 , 1

Therefore, roots of the equation whose roots are 1/alpha , 1/beta = -3/2 , 1

The equation is:

(x - (-3/2) )(x-1) = 0

=> (x+3/2)(x-1) = 0

=>x² + x/2 - 3/2 = 0

=> 2x² + x - 3 = 0