Question

if alpha and beta are the zeroes of p(x)=x^2-p(x+1)-c then show that (alpha+1)(beta+1)=1-c

Answer 1

let alpha be@
beta be $
@+$=p
@$=-p-c
(@+1)($+1)=@$+@+$+1
=-p-c+p+1
=1-c