If alpha and beta are the zeroes of p[x]=x2 + x-1,then find 1/alpha+1/beta
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Answered by
1
m representing here alpha by A and beeta by B , so we have
A+B=-1,
AB=-1,
then
1/A + 1/B =(B+A)/AB,
1/A + 1/B=(-1)/-1=1
A+B=-1,
AB=-1,
then
1/A + 1/B =(B+A)/AB,
1/A + 1/B=(-1)/-1=1
Answered by
0
1A PLUS 1B..........equas to BA
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