Question

If alpha and beta are the zeroes of polynomial 2x^2+x-3 find the value of alpha ×beta+1÷alpha÷1÷beta​

Answer 1

Step-by-step explanation:

Alpha + beta = -1/2

Apha × beta =-3/2

Alpha × beta + 1/alpha +1/ beta

= -3/2 +(alpha+beta)/alpha × beta

= -3/2+(-1/2)/(-3/2)

= -3/2+1/3

= (-9+2)/6

= -7/6

Further query in message box

Answer 2

Answer:

-7/6 is correct answer ok