If alpha and beta are the zeroes of polynomial 4x^2 - 2x + (K-4) and alpha =1 / beta. find the value of K
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Answer:
k=8
Step-by-step explanation:
the standard form for an quadratic equation is ax²+bx+c=0
α+β= -b/a and αβ= c/a
the given quadratic equation is 4x²-2x+(k-4)=0
here c = k-4
given that α=1/β which implies
αβ=1 .........(1)
from the given equation:
αβ=(k-4)/4.........(2).
comparing (1) and (2)
(k-4)/4=1
k-4=4
k=4+4=8
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