If alpha and beta are the zeroes of polynomial 4x2+3x+7, find value of alpha square+beta square
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4x² + 3x + 7
a and ß are the zeroes of the polynomial.
- - cofficient of x / cofficient of x²
- -3/4
- constant term / cofficient of x²
- 7/4
- a² + ß²
- (a+ß)²=a²+ß²+2aß
- a² + ß² = (a+ß)² - 2aß
- (a+ß)² - 2aß
- (-3/4)² - 2(7/4)
- 9/16 - 14/4
- 9 - 56 /16
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