If alpha and beta are the zeroes of polynomial 6x^2+x-2 then find alpha/beta+beta/alpha
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Answered by
1
alpha 1/2
beta -2/3
by spilitimg mid. term
beta -2/3
by spilitimg mid. term
somanshuk:
Thank you but i only want the answer for verifying not thesolution
thanks man
Answered by
6
Hi friend,
P(X) = 6X²+X-2
=> 6X²+4X-3X-2
=> 2X(3X+2)-1(3X+2)
=> (3X+2) (2X-1)
=> 3X +2 = 0. OR 2X -1 = 0
=> 3X = -2. OR 2X = 1
=> X = -2/3. OR X = 1/2
Alpha = -2/3 and Beta = 1/2
Therefore,
Alpha/Beta + Beta/Alpha = -2/3 ÷ 1/2 + 1/2÷-2/3
=> -2/3×2/1 + 1/2 ×-2/3
=> -4/3 + (-2/6)
=> -4/3 -2/6
=> -4×2 -2 × 1 /6
=> -8-2/6 = -10/6 = -5/3
Hence,
Alpha/Beta + Beta/Alpha = -5/3
HOPE IT WILL HELP YOU..... :-)
P(X) = 6X²+X-2
=> 6X²+4X-3X-2
=> 2X(3X+2)-1(3X+2)
=> (3X+2) (2X-1)
=> 3X +2 = 0. OR 2X -1 = 0
=> 3X = -2. OR 2X = 1
=> X = -2/3. OR X = 1/2
Alpha = -2/3 and Beta = 1/2
Therefore,
Alpha/Beta + Beta/Alpha = -2/3 ÷ 1/2 + 1/2÷-2/3
=> -2/3×2/1 + 1/2 ×-2/3
=> -4/3 + (-2/6)
=> -4/3 -2/6
=> -4×2 -2 × 1 /6
=> -8-2/6 = -10/6 = -5/3
Hence,
Alpha/Beta + Beta/Alpha = -5/3
HOPE IT WILL HELP YOU..... :-)
me too
Then i which school and which board
cbse
Me too in cbse dav
Are you both on Facebook
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