If alpha and Beta are the zeroes of polynomial p(x) = ax² + bx+c (a is not equal to 0, c is not equal to 0), find the quadratic polynomial with zeroes (-1/alpha) and (-1/beta).
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Answer:
zeroes =(-1)&(-1)
formula = x²-(sum of zeroes)x +(product of zeroes)
x²-(-1-1)x+[(-1)×(-1)]
x²-(-2)x +(1)
x²+2x +1
hence, the answer is x²+2x+1
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