Question

if alpha and beta are the zeroes of polynomial x2-5x+6 then find the value of 1upon alpha+1upon beta-2alpha*beta

Answer 1

Solution:

It is given that à and ß are the zeroes of polynomial x²- 5x+6

Let Polynomial be f(x) = x²- 5x+6

{ On comparing; a = 1 , b = -5 and c = 6 }

Here, Relationship Between Zeros:

☞ Sum of Zeroes = -b/a

= -(-5)/1

= 5

☞ Product of Zeros = c/a

= 6/1

= 6

Now, We have to Find the Value of 1/à + 1/b - 2àß

☛ 1/à + 1/b - 2àß

= à+ß/àß - 2àß

= 5/6 - 2*6

= 5/6 - 12

= 5-72

= - 67

Therefore, Value of 1/à + 1/b - 2àß is -67.

Answer 2

Solution:

It is given that a and ß are the zeroes of polynomial f(x) = x²- 5x+6

On comparing the Polynomial, We have; a = 1 , b = -5 and c = 6

Zeros of Polynomial :

Sum of Zeroes = -b/a

= -5/1

= 5

Product of Zeros = c/a

= 6

ACCORDING TO THE QUESTION:

⬇

{ Find the Value of 1/a+ 1/b - 2aß }

1/a + 1/b - 2aß

= a+ß/aß - 2aß

= 5/6 - 2×6

= 5/6 - 12

= 5-72

= - 67

Therefore, Answer is - 67 .