If alpha and beta are the zeroes of polynomial x²- 6x + k find the value of k such thsalpha square plus beta square = 40
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Α,b are the zeros of x²-6x+k=0
then, α+β=-(-6/1)=6 and α×β=k/1=k
now given that, (α+β)²-2αβ=40
or, 6²-2k=40
or, 36-2k=40
or, -2k=40-36
or, -2k=4
or, k=4/-2
or, k=-2
then, α+β=-(-6/1)=6 and α×β=k/1=k
now given that, (α+β)²-2αβ=40
or, 6²-2k=40
or, 36-2k=40
or, -2k=40-36
or, -2k=4
or, k=4/-2
or, k=-2
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