If alpha and beta are the zeroes of ppolynomial 3x2-2x-1 then find the value of alpha÷beeta+beeta÷alpha
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Step-by-step explanation:
=>3x^2-2x-1
By using splitting the middle term we get
=>3x^2-3x+x+1=0
=>3x(x-1)+(x-1)=0
=>(x-1)(3x+1)=0
Thus the zeros of the polinomial be a, b where a, b are 1 and - 1/3 respectively
WE have to find a/b+b/a
Taking LCM we get (a^2+b^2)/ab
=>(1+1/9)/(-1/3)
=>(10/9)/(-1/3)
=>-10/3
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