Math, asked by gauravnagra93992, 7 months ago

if alpha and beta are the zeroes of quadratic polynomial x^2-33x +7 find a quadratic polynomial whose zeroes are 1/alpha and 1/beta​

Answers

Answered by Anonymous
3

if

 \alpha  \: and \:  \beta

are the roots of equation

 {x}^{2}  - 33x + 7

then ,

 \alpha  +  \beta  =

- ( co efficient of x ) / co efficient of = - (-33) / 1 = 33

and

 \alpha  \beta  =

constant / co efficient of = 7 / 1 = 7

SO ,

 \frac{1}{ \alpha }  +  \frac{1}{ \beta }  =

=> Sum of new roots ,

 \frac{(  \:  \alpha  +  \beta  \: )}{ \alpha  \beta }  =  \frac{33}{7}

=> Product of new roots =

 \frac{1}{ \alpha }  \times  \frac{1 }{ \beta }  =  \frac{1}{ \alpha  \beta }  =   \frac{1}{7}

SO , new equation with roots ,

 \frac{1}{ \alpha } \:  \:  and \:  \:  \frac{1}{ \beta }

is ,

=> - ( sum of new roots ) x + product of new roots

=> {x}^{2}  +  \frac{33}{7} x +  \frac{1}{7}

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